SOLUTION: For the function defined by:
f(x)=
{x^2, x≤1}
{2x+1, x>1}
a. Evaluate f(0)
Algebra.Com
Question 1001754: For the function defined by:
f(x)=
{x^2, x≤1}
{2x+1, x>1}
a. Evaluate f(0)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
f(0)=0^2=0
You evaluate it at x is less than equal to one, so you do not consider the other part of the piecewise function.
RELATED QUESTIONS
evaluate the piecewise defined function at the indicated values
X^2+4x if x ≤... (answered by Fombitz)
Piecewise confuse me. Please help me understand this equation.
Evaluate the piecewise (answered by TimothyLamb)
Linear Function - Graph and evaluate the given formula:
f(x){ x^2 + 1 ; x ≤ 0
{ (answered by solver91311)
For the function defined by f(x)=2x-x^2, 0< or equal to x, use a sketch to help find a... (answered by stanbon)
For the function f defined by f(x)=x^+7 evaluate each expression
1.1 f(3a)
1.2... (answered by Alan3354)
For the following piecewise defined function find f(-1)
f(x)={x^2+1,......x<0... (answered by )
For the following piecewise defined function find f(1)
f(x) = {x^2+1,....x<0... (answered by longjonsilver)
Evaluate the piecewise defined function at the indicated values.
x^2+4x
x... (answered by ikleyn)
The set {(x,y)}|x=0
The domain of the functioned defined by f(x)=√3-x is the set... (answered by ikleyn)