Questions on Algebra: Functions, Domain, NOT graphing answered by real tutors!

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Question 151708: This is another Domain question that I would like to have answered because it contains the square root and is different from the first one submitted.
f(x)=cubed x+6 If I get my symbols right. Its the old division sign with a check on the beginning. You can tell I'm old school going back to school after 36 years.:-)
Thank you for your help.: This is another Domain question that I would like to have answered because it contains the square root and is different from the first one submitted.
f(x)=cubed x+6 If I get my symbols right. Its the old division sign with a check on the beginning. You can tell I'm old school going back to school after 36 years.:-)
Thank you for your help.
Answer by jim_thompson5910(9166) About Me  (Show Source):
You can put this solution on YOUR website!
Is the function f(x)=root(3,x+6) ??


With odd roots (ie roots with odd indices), we don't have to worry about domain restrictions.


Since we can plug in any value we want for x, this means that the domain is all real numbers.


So the domain of the function in set-builder notation is:





In plain English, this reads: x is the set of all real numbers (In other words, x can be any number)


Also, in interval notation, the domain is: