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put this solution on YOUR website!What is the sum of the infinite progression 3/2, 1, 2/3, 4/9 ......?
This is a geometric progression and the sum to infinity for geometric progressions when the magnitude of the ratio is less than 1 is a/(1-r), where a is the first term and r is the ratio.
In this example, a = 3/2, r = 2/3, therefore 1-r = 1/3
Therefore, the sum to infinity = (3/2)/(1/3) = (3 x 3)/(2 x 1) = 9/2 = 4.5
