SOLUTION: a). Find the function f such that f'(x) = 2sin(x) + sec^2(x) and f(0) = 3 b) Find the horizontal asymptote(s) of the graph of: y = (2x^2+5)/(3-x^2) I got: y=-2 because for

Question 999328: a). Find the function f such that f'(x) = 2sin(x) + sec^2(x) and f(0) = 3
b) Find the horizontal asymptote(s) of the graph of: y = (2x^2+5)/(3-x^2)
I got: y=-2 because for horizontal you check the exponents and they are the same here so -2 would make the most sense, I think.
a I have no idea how to solve
Please explain
Thank you
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Integrating the function gives you.

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Yes, correct.

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