SOLUTION: To three decimal places, find the value of the first positive x-intercept for the function f(x) = 2cos(x + 1).
ANSWER CHOICES:
0.571
1.571<--- MY ANSWER
1.081
2.571
Algebra.Com
Question 985068: To three decimal places, find the value of the first positive x-intercept for the function f(x) = 2cos(x + 1).
ANSWER CHOICES:
0.571
1.571<--- MY ANSWER
1.081
2.571
Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
f(x) should be to to find x-intercept
it is possible only if x+1 =pi/2
x+1 =1.5707
x=0.5707
result : 0.5707 (0.571)
RELATED QUESTIONS
1. If f(x) abd g(x) =1^x/3, find the indicated function value. If the result is... (answered by rapaljer,hellyeah)
1) Find the vertex, the line of symmetry, and the max or min value of f(x). Graph the... (answered by solver91311)
if f(x)=2cos^2 x+sin x-1 find the value of f(pi/2) (answered by stanbon)
Given the function y = 2cos(3x) + 1, determine the three functions f(x), g(x), and h (x)... (answered by ikleyn,greenestamps)
Could you please tell me if these are correct. Thank-you!
1. Give exact and approximate... (answered by solver91311)
Hi!
Find the local maximum and minimum values of the function and the value of x at... (answered by solver91311)
Evaluate:
7
(8x2 + 8x - 18) dx
-4
(2 decimal places)
Evaluate:
8
(answered by stanbon)
For the functionβ below, find theβ value(s) of x in which f'(x)=0.... (answered by math_tutor2020,MathLover1)
Find the domain f(x)=1/(1-2cos x) (answered by greenestamps)