SOLUTION: A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 100 feet per second from an initial height of 54 feet off the g
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Question 984117: A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 100 feet per second from an initial height of 54 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation:
h=−16t2+100t+54
Find the two points in time when the object is 99 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).
Answer: The object is 99 feet off the ground at the following times:
Enter your two answers separated by a comma.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Set the function equal to 99 and solve for the two roots of the quadratic equation.
John
My calculator said it, I believe it, that settles it
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