SOLUTION: question 1: Before a TV set leaves the factory it is given a quality control check. The probability that the TV contains zero, one or two defects is .88, .08 and .04 respective
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Question 978018: question 1: Before a TV set leaves the factory it is given a quality control check. The probability that the TV contains zero, one or two defects is .88, .08 and .04 respectively. In a sample of 16 TVs, find the probability that 9 will have no defects, 4 will have one defect and 3 will have two defects. Round your answer to 3 decimal places (beyond the zeros)
question 2: A lot of 20 typewriters contains four defectives. 5 typewriters are randomly selected, what is the probability that at least two of the typewriters are defective? Round your answer to four decimal places.
question 3: A jar contains 5 red, 6 white and 7 blue marbles. 5 marbles are randomly selected from the jar. Find the probability of drawing 2 red and 3 white marbles. Round your answers to 4 decimal places.
Select one:
a. .0233
b. .0286
c. .2907
d. .111
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Q3: Two red marbles can occur on the first or second draw or first and third, 10 ways altogether 5C2
The first probability is (5/18) the second is (4/17). The white marbles also have 10 ways they can be chosen (5C3=5C2) (6/16)(5/15)(4/14)
The denominators are always 18*17*16*15*14. The numerators are always 5*4*6*5*4. There are 10 ways to place the red balls. Once they are placed, the white balls have no choice. So there is one 10 in the numerator, not 2.
10*2400/18*17*16*15*14=0.0233 A
Q2:Probability of at least 2 = 1- probability of 1-probability of 0.
Probability no defective is (16/20)(15/19)(14/18)(13/17)(12/16)=0.0188
Probability of 1 defective is (16/20)(15/19)(14/18)(13/17)(4/16) *5 The defective typewriter can be 1st-5th, but the denominators stay the same, There are 5 ways it can happen.
This probability is 0.4696
The total of the two is 0.4884
Subtract from 1, and the probability of at least 2 is 0.5116.
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