SOLUTION: Will someone solve and explain this question: Q: Mr. Sim invests $9000 at 2% per annum compound interest compounded daily. What is this amount at the end of the third day?

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Question 970240: Will someone solve and explain this question:
Q: Mr. Sim invests $9000 at 2% per annum compound interest compounded daily. What is this amount at the end of the third day?

Found 2 solutions by LinnW, AnlytcPhil:
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
At 2% per year, the daily interest rate is ( 2% / 365 ).
( 2% / 365 ) = 0.02/365 = 0.0000547945
We need to apply the interest rate over 3 days.
If r is the rate of interest for one day,
(1+r)(1+r)(1+r)*9000 will give us the amount in the account
after 3 days.
(1+r)(1+r)(1+r) = (1+r)^3
so (1+r)(1+r)(1+r)*9000 = (1+r)^3*9000
Since r = 0.0000547945
(1+r)^3*9000 = (1+0.0000547945)^3*9000
= (1.0000547945)^3*9000
= 1.000164392507476207796812933625 * 9000
= approximately 9001.47953

Answer by AnlytcPhil(1807) About Me  (Show Source):
You can put this solution on YOUR website!
P=9000
R=0.02
N=360   (banks use 360 days a year, because they got started before
         calculators or computers were invented.  It was easier to
         do arithmetic by hand using 360 than 365, and they've never
         changed)
  
T=3/360 (3 days is 3/360th of a year)

Formula:

P%22%22=%22%22A%281%2BR%2FT%29%5E%28N%2AT%29

P%22%22=%22%229000%281%2B0.02%2F%28%28%223%2F360%22%29%29%29%5E%28360%2A%28%223%2F360%22%29%29

P%22%22=%22%22%249001.50

Edwin