SOLUTION: Consider kx2 + 10x ¡ 5 = 0. Find k for which the equation has: a a repeated root b two distinct real roots.

Algebra.Com
Question 965336: Consider kx2 + 10x ¡ 5 = 0. Find k for which the equation has:
a a repeated root b two distinct real roots.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Consider kx2 + 10x ¡ 5 = 0. Find k for which the equation has:
a a repeated root b two distinct real roots.
---------------
What does 10x ¡ 5 mean?

RELATED QUESTIONS

Find k such that the equation 6x^2 + 6x + k =0 has Two equal real roots, two distinct... (answered by MathLover1,josmiceli,MathTherapy)
Find k such that the equation 2x^2 +kx + 8 = 0 has two equal real roots, two distinct... (answered by MathLover1,MathTherapy)
could someone assist me on how i can crack this problem it says in the quadratic equation (answered by Theo)
The equation x^2+(k+2)x+2k=0 has two distinct real roots. Find the possible values of... (answered by ikleyn)
Find k such that the equation 2x^2 +kx + 8 has two equal real roots, two distinct real... (answered by Alan3354)
Given the discriminant k^2+12k+20, find the values of k for its quadratic equation has... (answered by Alan3354,josgarithmetic,ikleyn)
Find the values of k so that the equation {{{(k-2)x^2+4x-2k+1=0}}} has two distinct real... (answered by josgarithmetic)
The equation x^2 + k = 6 x has two distinct real roots. Find the range of values of k. (answered by stanbon)
Find k such that the equation x^2 - kx + 4 = 0 has a repeated real solution. (answered by Shin123)