SOLUTION: X^2(2x^2+1)^2/(x-1)*(4x^3-6x^2+x-2)/x(x-1)(2x^2+1)Can anyone please show me how simply this fraction.

Question 938981: X^2(2x^2+1)^2/(x-1)*(4x^3-6x^2+x-2)/x(x-1)(2x^2+1)Can anyone please show me how simply this fraction.
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
The expression can too easily be misunderstood. If what you wrote is rendered to appear more normal in notation, this is it:

Is that what you have?

"Yes"....
The rendered expression has a couple of obvious factors of 1. You could eliminate and . You still want to try to factorize the cubic expression factor found in the numerator.

If you know polynomial division, you should divide 4x^3-6x^2+x-2 by x-1. If remainder is 0, then you have just found two factors of 4x^3-6x^2+x-2.
....In fact, remainder is -3. This means that no other possible factors to check for it in the denominator.

You have then once simplifications done,

The last thing to do is multiply the polynomials of the numerator, and multiply (square) the binomials of the denominator.
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