SOLUTION: A dentist invested a portion of $14,000 in a 8% annual simple interest account and the remainder in a 6.5% annual simple interest government bond. The two investments earn $1045 in

Question 934825: A dentist invested a portion of $14,000 in a 8% annual simple interest account and the remainder in a 6.5% annual simple interest government bond. The two investments earn $1045 in interest annually. How much was invested in each account? in the 8%_____ and in the 6.5%______
HELP ME!!! =o)))) PLEASE
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
x = amount (in dollars) invested in the 8% account
y = amount (in dollars) invested in the 6.5% account

$14,000 was invested in only two accounts, which means x and y must add to 14,000

x+y = 14000
y = 14000-x

I solved for y so I could plug it into the next equation below

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Now set up the second equation and plug in y = 14000-x. Then solve for x

0.08x + 0.065y = 1045
0.08x + 0.065(14000-x) = 1045
0.08x + 0.065(14000)-0.065(x) = 1045
0.08x + 910-0.065x = 1045
0.015x + 910 = 1045
0.015x = 1045 - 910
0.015x = 135
x = 135/0.015
x = 9000

Use this to find y

y = 14000-x
y = 14000-9000
y = 5000

How much was invested in each account?

in the 8% __

___
and in the 6.5%___

___
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