SOLUTION: A ball is thrown across a playing field. Its path is given by the equation y = −0.005 x^2 + x + 6 , where x is the distance the ball has traveled horizontally, and y is its h
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Question 906061: A ball is thrown across a playing field. Its path is given by the equation y = −0.005 x^2 + x + 6 , where x is the distance the ball has traveled horizontally, and y is its height above ground level, both measured in feet.
(a) What is the maximum height attained by the ball?
(b) How far has it traveled horizontally when it hits the ground?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Find
The x-coordinate of the vertex is located at
and
(a)
The max height is 56 ft
(b)
It hits the ground when
Multiply both sides by
When it hits the ground, it has traveled 205.83 ft
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Here's the plot:
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