SOLUTION: 4/w^2-11/w+6=0
Algebra.Com
Question 903511: 4/w^2-11/w+6=0
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Substitute.
Let .
Two solutions:
and
RELATED QUESTIONS
Solve by using the quadratic formula.
4/w^2-11/w+6=0
(answered by richwmiller)
-2(w+4)+9<-11
(answered by rfer)
-2(w+4)+9<-11 (answered by jim_thompson5910)
(w^-4)/(w^6) (answered by gwendolyn,ewatrrr)
(w-w^2)^4 (answered by tommyt3rd)
5. Factor completely: w^2+5w-24
(w+12)(w-2)
(w+6)(w-4)
(w-8)(w+3)
(w+8)(w-3) (answered by Alan3354)
(w-7/4+w+5/11)=(9/2)
(answered by cta1987)
please help me with
reduce your fraction
w^2+5w+6/ w^2-w-12
a. w-2/ w-4
b.... (answered by Fombitz)
7/w+45/w+4=6/w (answered by Maths68)