SOLUTION:
y^2=1-x^2
x-2y=4
(4, 0) and (0, -2)
No Solution
(0, 4) and (-2, 0)
(4, 2) and (0, 0)
Algebra.Com
Question 891624:
y^2=1-x^2
x-2y=4
(4, 0) and (0, -2)
No Solution
(0, 4) and (-2, 0)
(4, 2) and (0, 0)
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Required a substitution and then some detailed algebra steps - that was all. I solved this a few minutes ago in your other identical request. None of your choices were what I found.
Your system is a circle and a line.
and -2y=-x+4 or .
(While I was rechecking this posting, the graph would not display, even though the code and rendering tags seem to all be correct)
RELATED QUESTIONS
Solve.
y^2=1-x^2
x-2y=4
(4, 0) and (0, -2)
No Solution
(0, 4)... (answered by josgarithmetic)
please help me solve this equation
Solve.
y^2=1-x^2
x-2y=4
(4, 0) and (0,... (answered by josgarithmetic)
Please help with this equation:
2x+z+3w=0
-x+2y-z-2w=2
x-y+w=2
I did this:
2 0 1 (answered by Alan3354)
x^2-... (answered by helpnalgebra)
x^2 + 4 =... (answered by Alan3354)
Find the x- and y-intercepts. If no x-intercepts exist, state so.
f(x) = x^2 - 5x - 24
(answered by checkley77)
x / y
0.0 0.0
0.2 1.8
0.4 3.2
0.6 4.2
0.8 4.8
1.0 5.0
1.2 4.8... (answered by ikleyn)
(x+1)2-4=0 (answered by mananth)
y=2
x|0|2|4|
y| | |... (answered by Fombitz)