SOLUTION: FIVE Years hence, a boys age will four times the square of his age nine years ago.
how old is the boy now?
Algebra.Com
Question 889019: FIVE Years hence, a boys age will four times the square of his age nine years ago.
how old is the boy now?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
FIVE Years hence, a boys age will four times the square of his age nine years ago.
how old is the boy now?
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Equation:
Let his age "x"::
x + 5 = 4(x-9)^2
x + 5 = 4[x^2 - 18x + 81]
x + 5 = 4x^2 - 72x + 324
4x^2 -73x + 319 = 0
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x = 11 years
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Cheers,
Stan H.
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