Hi,
2x-4y=-1 &
y=x-1
finding the point of Intersection or the 'solution' to this system of EQs
2x - 4y = -1
2x - 4(x-1) = -1 |Substituting for y
-2x +4 = -1
-2x = -5
x = (5/2) and y = (3/2) (x-1)
Pt (5/2, 3/2) is the solution for this system of EQs (the lines intersect at that point)