SOLUTION: Find the value to 1dp of x if 5xsquared+3x=105

Question 805819: Find the value to 1dp of x if 5xsquared+3x=105
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the value to 1dp of x if 5xsquared+3x=105
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5x^2 + 3x -105 = 0
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Use the Quadratic Formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [-3 +- sqrt(9-4*5*-105)]/(10)
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x = [-3 +- sqrt(2109)]/10
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x = (-3+sqrt(2109))/10 or x = (-3-sqrt(2109))/10
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x = 4.29 or x = -4.89
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Cheers,
Stan H.
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