SOLUTION: Find all points on the y-axis (that is, having coordinates (0,y), where y is to be determined) that are 6 units distant from the point (4, -3). Thank you in advance

Question 775724: Find all points on the y-axis (that is, having coordinates (0,y), where y is to be determined) that are 6 units distant from the point (4, -3). Thank you in advance
Found 2 solutions by josgarithmetic, psbhowmick:
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
Shortest distance to the y axis is what is helpful. No change in y value, from y=-3. You would form a triangle. One point is the given point (4, -3). Another point is (0, -3) which is the distance TO the y axis. The last point is ON the y axis but 6 units from (4, -3). You just need the Distance Formula.

In fact, you might try this with just Pythagorean Theorem, and then avoid formal use of Distance formula. You have two lengths. One is 6 units, the other is 3 units. Size of the other leg?
, since the hypotenuse is 6 units.

units long, but really, or .

Up 5 units from -3 is -3+5=2.
Down 5 units from -3 is -3-5=-8.

The answer for the point is then either or both of (0,2) or (0,-8).
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
Let a point on y-axis whose distance from (4,-3) is 6 units be having coordinates (0,k).

The distance between these two points must be 6 units.

Therefore there are two such points: (,) and (,)
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