SOLUTION: One year, Don invested a total of $40,000, part at 4%, part at 5%, and the rest at 5.5%. The amount of interest received on the investments was $1990. The interest received on the
Algebra.Com
Question 764622: One year, Don invested a total of $40,000, part at 4%, part at 5%, and the rest at 5.5%. The amount of interest received on the investments was $1990. The interest received on the 5.5% investment was $590 more than the interest received on the 4% investment. How much was invested at each rate?
I am having trouble solving this problem. I keep getting thrown off by the extra %. Any help would be greatly appreciated!
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
One year, Don invested a total of $40,000, part at 4%, part at 5%, and the rest at 5.5%. The amount of interest received on the investments was $1990. The interest received on the 5.5% investment was $590 more than the interest received on the 4% investment. How much was invested at each rate?
I am having trouble solving this problem. I keep getting thrown off by the extra %. Any help would be greatly appreciated!
Let the amount invested at 4% be F, and amount invested at 5%, E
Then amount invested at 5.5% = 40,000 (F + E), or 40,000 F E
Interest received on4%: .04F
Interest received on 5%: .05E
Interest received on 5.5%: .055(40,000 F E), or 2,200 - .055F - .055E
Since total interest received on all investments = 1,990, then:
.04F + .05E + 2,200 - .055F - .055E = 1,990
.04F - .055F + .05E - .055E = 1,990 2,200
- .015F - .005E = - 210 ----- eq (i)
Also, 2,200 - .055F - .055E = .04F + 590
.04F + .055F + .055E = 2,200 - 590
.095F + .055E = 1,610 ------ eq (ii)
We now have:
- .015F - .005E = - 210 ----- eq (i)
.095F + .055E = 1,610 ------- eq (ii)
0.165F - .055E = - 2,310 ------ Multiplying eq (i) by 11 -------- eq (iii)
0.07F = - 700 ------ Adding eqs (iii) & eq (ii)
F, or amount invested at 4% = , or $
- 150 .005E = - 210 ------ Substituting 10,000 for F in eq (i)
.005E = - 210 + 150
.005E = - 60
E, or amount invested at 5% = , or $
Amount invested at 5.5%: 40,000 (10,000 + 12,000), or 40,000 22,000, or $
You can do the check!!
Further help is available, online or in-person, for a fee, obviously. Send comments, thank-yous, and inquiries to D at MathMadEzy@aol.com
RELATED QUESTIONS
the total interest earned after one year Php 100 000 is invested, part of 6% annual... (answered by greenestamps)
A total of $12,000 was invested. Part of the money was invested at 4% and the rest... (answered by checkley79)
A person invested $9000, part at 4 1/2%p.a and the rest at 5% p.a. If the total interest (answered by macston)
Larry Mitchell invested part of his $30,000 advance at 5% annual simple interest and the... (answered by greenestamps)
What is the mathematical expression of this. The total interest earned after one year... (answered by Alan3354,ikleyn)
Brandon invested $20 000. He invested part of the money in a term deposit paying 4%... (answered by ikleyn,greenestamps)
Ron invested a total of $7,100, part at 5% simple interest and part 4% interest. At the... (answered by rfer)
Michael received $1,000 as a graduation gift. He invested part of the money at 5% and the (answered by checkley77)
Larry Mitchell invested part of his $31,000 advance at 5% annual simple interest and the... (answered by amoresroy)