SOLUTION: A block of mass 120 g moves with a speed of 6.0 m/s on a frictionaless horizontal surface towards another block ofmass 180 g kept at rest. They collide and the first block stops

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Question 732219: A block of mass 120 g moves with a speed of
6.0 m/s on a frictionaless horizontal surface
towards another block ofmass 180 g kept at rest.
They collide and the first block stops. Find the
speed of the other block after the collision.

send me step by step solution
Found 2 solutions by lynnlo, ikleyn:
Answer by lynnlo(4176)   (Show Source): You can put this solution on YOUR website!

Answer by ikleyn(53339)   (Show Source): You can put this solution on YOUR website!
.
A block of mass 120 g moves with a speed of 6.0 m/s on a frictionless horizontal surface
towards another block of mass 180 g kept at rest.
They collide and the first block stops. Find the speed of the other block after the collision.
~~~~~~~~~~~~~~~~~~~~~~~ 

Use the law of the momentum conservation

    120*6 = 180*v,

where v is the speed of the block of the mass 180 g.


From this equation

    v =  =  = 2*2 = 4 m/s.


ANSWER.  The speed of the other block after the collision is 4 m/s.

Solved.



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