SOLUTION: Hi, can you please help me? Ive tried this problem 9 times...and I keep getting it wrong... The answers I got was: 4, squareroot 3, and negative squarerroot 3 Thank you sooo much

Question 499115: Hi, can you please help me? Ive tried this problem 9 times...and I keep getting it wrong...
The answers I got was: 4, squareroot 3, and negative squarerroot 3
Thank you sooo much for your help! i hope you can help me... it would be soo appreciated! :)
Find all real solutions of the equation. (Enter your answers as a comma-separated list. If there is no real solution, enter NO REAL SOLUTION.)
x3 − 4x2 − 3x + 12 = 0
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
But you are right
;
x^3 - 4x^2 - 3x + 12 = 0
Factor by grouping
(x^3 - 3x) - (4x^2 - 12) = 0
x(x^2 - 3) - 4(x^2 - 3) = -
(x - 4) (x^2 - 3) = 0
x = 4
and
x^2 = 3
x =
x = -
:
Confirm this on a graphing calc

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