SOLUTION: a stone is thrown straight upward with a speed of 20m/s,it is caught on its way down at a point 5.0m above where it was thrown,how far was it going when it was caught,and how long
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Question 490857: a stone is thrown straight upward with a speed of 20m/s,it is caught on its way down at a point 5.0m above where it was thrown,how far was it going when it was caught,and how long did the trip take
Answer by ccs2011(207) (Show Source): You can put this solution on YOUR website!
Initial velocity = 20
h(t) = -4.9t^2 +20t
Solve for t when h(t) = 5
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Use quadratic formula
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We want the time when the stone is on its way down which will be the longer time
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Trip took 3.814 sec
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v(t) = -9.8t + 20
Solve for when t = 3.814
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Speed is always positive
Stone was traveling at 17.378 m/s when caught
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