SOLUTION: Find an equation of the line containing the points (-3, 1) and (-1, 3).

Question 315602: Find an equation of the line containing the points (-3, 1) and (-1, 3).
Found 3 solutions by jim_thompson5910, nyc_function, stanbon:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Add 1 to both sides.

Combine like terms.

Simplify

So the equation that goes through the points and is

Notice how the graph of goes through the points and . So this visually verifies our answer.
Graph of through the points and

Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
We first find the slope.
Let m = slope
m = (3 - 1)/(-1 -(-3))
m = 2/(-1 + 3)
m = 2/2
m = 1
The slope is 1.
We now use the point-slope formula.
y - y1 = m(x - x1)
Pick one of the given points and the slope 1 to plug into the poitn-slope formula.
y - 1 = 1(x - (-3))
y - 1 = 1(x + 3)
y - 1 = x + 3
y = x + 3 + 1
y = x + 4
Done!
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find an equation of the line containing the points (-3, 1) and (-1, 3).
-----------------------
slope = (3-1)/(-1--3) = 2/2 = 1
--------------------------------------
Form: y = mx + b
You know m = 1 and y = 1 when x = -3 ; solve for "b":
1 = 1*-3 + b
b = 4
----
Equation:
y = x + 4
=================
Cheers,
Stan H.
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