SOLUTION: Ok, I need help solving this equation and then graphing it, i am confused by this. Perpendicular to x + 2y = 10, and passing through the point (1,1) Thanks, Holly

Question 296324: Ok, I need help solving this equation and then graphing it, i am confused by this.
Perpendicular to x + 2y = 10, and passing through the point (1,1)
Thanks,
Holly
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
By "solving" you must mean..."Find the equation of the line that is perpendicular to x+2y = 10 and passing through the point (1, 1)".
First, let's find the slope of the given line x+2y =10.
Rewrite this equation in slope-intercept form: y = mx+b, where m is the slope and b is the y-intercept..
x+2y = 10 Subtract x from both sides.
2y = -x+10 Now divide both sides by 2.
y = (-1/2)x+5 Comparing this with...
y = mx+b you can see that the slope, m, of the given line is:
Now lines that are perpendicular to each other will have slopes that are the negative reciprocal. So if the slope of the given line is,, then the slope of any line perpendicular to it is, or so now you can start your answer with:
Now you need to find the value of b, the y-intercept. You do this by substituting the x- and y-coordinates from the given point (1, 1) into this equation. Substituting x = 1 and y = 1 you get...
Subtract 2 from both sides.

Now you can write the final equation:

The graph of this equation will look like:

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