SOLUTION: Find three consecutive odd numbers such that four times the first number decreased by 28 is the same as the sum of the last two numbers.

Question 294690: Find three consecutive odd numbers such that four times the first number decreased by 28 is the same as the sum of the last two numbers.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the three consequitive numbers be x, x+2 , x+4
4times the first number decreased by 28
=4x-28
this is equal to sum of second two numbers
x+2 and x+4
4x-28=x+4 +x+2
4x-28=2x+6
4x-2x= 28+6
2x=34
x=17
So the numbers are 17,19,21

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