SOLUTION: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?

Algebra ->  Algebra  -> Finance -> SOLUTION: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 231290: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?
Answer by rfer(2688) About Me  (Show Source):
You can put this solution on YOUR website!
.06x+.11(6000-x)=460
.06x+660-.11x=460
-.05x=-200
x=$4000 at 6%
$2000 at 11%