SOLUTION: Can you help-- Solve the system by the addition method. x/3-y/2=-5/6, x/5-y/3=-3/5 Thank you all

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 Click here to see ALL problems on Finance Question 194216: Can you help-- Solve the system by the addition method. x/3-y/2=-5/6, x/5-y/3=-3/5 Thank you all Answer by anantha(86)   (Show Source): You can put this solution on YOUR website!sol:x/3-y/2= -5/6 this is the 1st equation take l.h.s part the l.c.m of 3,2 is 6 multiplying by 6 on both sides of the equation (x/3)*6-(y/2)*6= -(5/6)*6 2x-3y= -5 --------(3 equation) x/5-y/3= -3/5 take l.h.s part the l.c.m of 5,3 is 15 multiplying both sides by 15 (x/5)*15-(y/3)*15= (-3/5)*15 3x-5y=-7 --------(4 th equation) solving these two equations we get x,y values 2x-3y= -5 3x-5y=-7 multiplying 3 equation by 3 on both sides and multiplying 4th equation by 2 on both sides 2x*3-3y*3= -5*3 3x*2-5y*2= -7*2 6x-9y= -15 6x-10y=-14 on solving these equations changin the symbols of 2nd equation 6x-9y= -15 -6x+10y= +14 -------------------- 0+1y= -1 y= -1 substitute this value in 3rd equation we get x value 2x-3y= -5 2x-3*(-1)= -5 2x+3= -5 subtracting 3 on both sides 2x+3-3= -5-3 2x=-8 dividing by 2 on both sides 2x/2= -8/2 x= -4 check these values correct or not substitute these values in 3rd equation 2x-3y= -5 2*(-4)-3*(-1)= -5 -8+3=-5 -5= -5 these two values satisfy the equations