SOLUTION: The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial speed of 65 meters per second can be modeled by the parabola: f(x)=

Question 184256: The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial speed of 65 meters per second can be modeled by the parabola: f(x)= x - 0.0023x2, where the x-axis is the ground. Find the height of the highest point of the trajectory and the horizontal distance the potato travels before hitting the ground.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with an initial speed of 65 meters per second can be modeled by the parabola: f(x)= x - 0.0023x2, where the x-axis is the ground. Find the height of the highest point of the trajectory and the horizontal distance the potato travels before hitting the ground.
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f(x)= x - 0.0023x^2
The highest point occurs when x = -b/2a = -1/(2*-0.0023) = 217.39 seconds
The height at that time is f(217.39) = 217.39 - 0.0023(217.39)^2
= 108.7 ft.
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Distance when it hits the ground?;
Distance will 2(217.39) = 434.78 feet
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You can get this result by solving
x - 0.0023x^2 = 0 since zero is the hight of the potato when it hits the ground.
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Cheers,
Stan H.
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