SOLUTION: A chemist has 2 alloys, 1 of which is 10% gold and 20% lead, and the other of which is 30% gold anf 35% lead. How many grams of each of the 2 alloys should be used to make an alloy

Question 173061: A chemist has 2 alloys, 1 of which is 10% gold and 20% lead, and the other of which is 30% gold anf 35% lead. How many grams of each of the 2 alloys should be used to make an alloy that contains 63g of gold and 111g of lead?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A chemist has 2 alloys, 1 of which is 10% gold and 20% lead, and the other of which is 30% gold anf 35% lead. How many grams of each of the 2 alloys should be used to make an alloy that contains 63g of gold and 111g of lead?
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Gold Equation: 0.10x + 0.30y = 63
Lead Equation: 0.20x + 0.35y = 111
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Use whatever method you know to solve this system to get:
x = 450 grams (amt of the 1st alloy in the final mixture)
y = 60 grams (amt of the 2nd alloy in the final mixture)
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Cheers,
Stan H.
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