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Question 149706: I tried to find an equation with the the unknown amount of coins but could not find one. I believe I need 3 seperate equations but I am not sure.
.05N+.10D=5.65
.05N+2 + .10D*2
(Not sure if this one is right. don't know the third one but I am pretty sure there is one Please help)

Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?: I tried to find an equation with the the unknown amount of coins but could not find one. I believe I need 3 seperate equations but I am not sure.
.05N+.10D=5.65
.05N+2 + .10D*2
(Not sure if this one is right. don't know the third one but I am pretty sure there is one Please help)

Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by stanbon(18743) (Show Source):
You can put this solution on YOUR website!
Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
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Value EQUATION: 5N + 10D = 565
Value EQUAT: 5(N+8) + 10(2D) = 1045
----------------------------
Rearrange:
5N + 10D = 565
5N + 20D = 1045 - 80
----------------------------
Subtract 1st from 2nd to get:
10D = 400
D = 40 (# of dimes)
----------------
Substitute to solve for N:
5N + 400 = 565
5N = 165
N = 33 (# of nickels)
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Cheers,
Stan H.