SOLUTION: A company finds that it can make a profit of P dollars each month by selling x patterns, according to the formula P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each mon

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Question 1204337: A company finds that it can make a profit of P dollars each month by selling
x patterns, according to the formula
P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each month to have a maximum profit?
To attain maximum profit they must sell
patterns.
What is the maximum profit?
The max profit is $

Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
A company finds that it can make a profit of P dollars each month by selling
x patterns, according to the formula
P(x)=-.002x^2+5.5x-1400. How many patterns must it sell each month to have a maximum profit?
To attain maximum profit they must sell
patterns.
What is the maximum profit?
The max profit is $
~~~~~~~~~~~~~~~~~~~~~~~~~~

They want you find the maximum of the quadratic function  P(x) = ax^2 + bx + c = -0.002x^2 + 5.5x - 1400.


The general theory says that the maximum is attained at   =  =  =  = 1375.


To get the value of the maximum profit, substitute this value  = 1375 into the formula for the profit.
You will get

     = -0.002*1375^2 + 5.5*1375 - 1400 = 2381.25  dollars.


ANSWER.   = 1375 patterns.

          = 2381.25  dollars.

Solved.

--------------------

On finding the maximum/minimum of a quadratic function see the lessons
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola


Consider these lessons as your textbook,  handbook,  tutorials and  (free of charge)  home teacher.
Learn the subject from there once and for all.



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