SOLUTION: A cyclist rides over a hill , a total journey of 9km. His average speed uphill is 8km/hr and his average speed downhill is 20km/hr . If the journey takes 45minutes , find the dista

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Question 1201528: A cyclist rides over a hill , a total journey of 9km. His average speed uphill is 8km/hr and his average speed downhill is 20km/hr . If the journey takes 45minutes , find the distance he rode uphill.( the answer is 4km)
Now , this is how I worked it out :
I took 8 km/hr and 9km and divided them (since time=distance/speed)
so 9/8hrs he took uphill. and then I did 8km/hr multiplied by 9/8hrs which is 9.
so distance uphill which is 9cm . but that is the total journey given . How do you work this out please?

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
A cyclist rides over a hill , a total journey of 9 km. His average speed uphill is 8 km/hr
and his average speed downhill is 20 km/hr. If the journey takes 45minutes, find the distance he rode uphill.
~~~~~~~~~~~~~~~~~~

Let x is the distance uphill, in kilometers.
Then the distance downhill is (9-x) kilometers.


The time travel uphill is    hours  (distance divided by the speed).

The time travel downhill is    hours  (due to the same reason).


The total time is 3/4 of an hour, giving you an equation

     +  =    of an hour.


    +----------------------------------------------+
    |       At this point, the setup is done.      |
    |    Now your task is to solve the equation.   |
    +----------------------------------------------+


For it, multiply the equation by 80 (both sides).  You will get

    10x + 4*(9-x) = 

    10x + 36 - 4x = 3*20

    10x - 4x       = 60 - 36 

        6x         =    24

         x         =    24/6 = 4 kilometers.


ANSWER.  The distance uphill is 4 kilometers.


CHECK.  0.5 of an hour is spent to travel 4 km uphill at 8 km/h.

        3/4 - 1/2 = 1/4 of an hours remained.

        It was spent to travel (9-4) = 5 km downhill at the speed of 20 km/h.  ! correct !

Solved.


It is one of possible ways to solve the problem.

There are other ways, too.

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See the lesson
    - Using time equation to solve some Travel and Distance problems
in this site.  Find there the solutions for other similar  (and different)  problems.



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