SOLUTION: : A man bought 15 books for #9800. Some of these books cost #600 each and the rest cost #700 each. How many of each type did he buy.

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Question 1198001: : A man bought 15 books for
#9800. Some of these books cost #600 each
and the rest cost #700 each. How many of
each type did he buy.
Found 3 solutions by Alan3354, ikleyn, josgarithmetic:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
: A man bought 15 books for
#9800. Some of these books cost #600 each
and the rest cost #700 each. How many of
each type did he buy.
------------------
x + y = 15
600x + 700y = 9800
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
A man bought 15 books for #9800.
Some of these books cost #600 each and the rest cost #700 each.
How many of each type did he buy.
~~~~~~~~~~~~~~~~~~ 

If all 15 books cost #600 each, the total would be 15*600 = 9000.


Comparing it with #9800, we conclude that 8 books cost #700 each, 
while the rest 15-8 = 7 books cost #600 each.


ANSWER.  7 books at #600 each and 8 books at 700 each.


CHECK.  7*600 + 8*700 = 4200 + 5600 = 9800, which is precisely correct.

Solved mentally, without using equation/equations, by mental reasoning, only.



Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
x, how many lowprice books
y, how many high price books
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