SOLUTION: A metallurgist has one alloy containing 43% aluminum and another containing 63% aluminum. How many pounds of each alloy must he use to make 43 pounds of a third alloy containing 49
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Question 1197807: A metallurgist has one alloy containing 43% aluminum and another containing 63% aluminum. How many pounds of each alloy must he use to make 43 pounds of a third alloy containing 49% aluminum?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
A type of mixture problem asked very frequently. There are millions of these answered.
43% and 63%;
want mixture 43 pounds of 49%;
L=43
H=63
T=49
M=43, pounds of the mixture
y, unknown pounds of the H% alloy (63% alloy)
-
and you can find .
Substitute your given values.
--
How much pounds the 63%:
------pounds of the 63% Al alloy
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