SOLUTION: A boy has 93 cents in pennies, nickels, dimes, and quarters. He has two more quarters than dimes. If he has as many nickles as dimes and as many pennies as quarters, how many of ea

Question 119676: A boy has 93 cents in pennies, nickels, dimes, and quarters. He has two more quarters than dimes. If he has as many nickles as dimes and as many pennies as quarters, how many of each coin does he have?
He has _____ penny(s), _____ nickel(s), _____ dime(s), and _____ quarter(s).
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x=dimes, so x=nickels, x+2=quarters and x+2=pennies

x(10)+x(5)+(x+2)(25)+(x+2)(1)=93

10x+5x+25x+50+x+2=93 __ 41x+52=93
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