SOLUTION: A student who has not studied for a multiple-choice test decides to guess the answers for every
question. There are three questions, and three choices of answer (A, B and C) for
Question 1195726: A student who has not studied for a multiple-choice test decides to guess the answers for every
question. There are three questions, and three choices of answer (A, B and C) for each question. Given
that only one of the possible choices (A, B or C) is correct for each question, state the probability that
the student guesses:
a 1 correct answer b 2 correct answers c 3 correct answers d 0 correct answer Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
There are 3*3*3 = 27 possible outcomes
# correct Formulation Probability Notes
0 (2/3)*(2/3)*(2/3) 8/27
1 3C1*(1/3)*(2/3)*(2/3) 12/27 3C1 = 3!/(2!*1!) = 3
2 3C2*(1/3)*(1/3)*(2/3) 6/27 3C2 = 3!/(1!*2!) = 3
3 (1/3)*(1/3)*(1/3) 1/27