SOLUTION: solve the value of x when y>0 and z<0, 2xyz+yz answer must be more than 3xyz
Algebra.Com
Question 1194282: solve the value of x when y>0 and z<0, 2xyz+yz answer must be more than 3xyz
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
I have no idea what this is supposed to mean....
There is no equation, so there is nothing to "solve".
If you are serious about getting help with your question, take the time to present it clearly. Proper English and maybe even some punctuation would help....
Re-post....
RELATED QUESTIONS
Hi,
How do I solve this inequality?
GIven that y is always positive and z is always (answered by rothauserc,ikleyn)
Hi,
If x= log of 2 to the base 15; y= log of 3 to the base 10 and z=log of 5 to the... (answered by lwsshak3)
If (x^2)(y^3)z < 0, which of the following statements must be true?
I. yz < 0
II. xz... (answered by richard1234)
Find the value of c and YZ if Y is between X and Z.
XY=11, YZ=4c,... (answered by mananth)
Find the value of the variable YZ if Y is between X and Z.
XY=11, YZ=4c,... (answered by Fombitz)
-3xyz(squared)
x=-4 y=-2 z=1\2
okay when i put this equation in my TI calculator i... (answered by nerdybill)
if x²+y²+z²-64/xy-yz-zx=-2 and x+y=3z,than value of z... (answered by Edwin McCravy)
If x=log15 2, y= log10 3, z=log6 5; prove that xy + yz + zx + 2xyz =... (answered by robertb)
SOLUTION: If x=log15 2, y= log10 3, z=log6 5; prove that xy + yz + zx + 2xyz =... (answered by ikleyn)