SOLUTION: A shipment of 10 items has two defective and eight non defective units.In the inspection of the shipment , a sample of units will be selected and tested. If a defective unit is fou

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Question 1193401: A shipment of 10 items has two defective and eight non defective units.In the inspection of the shipment , a sample of units will be selected and tested. If a defective unit is found , the shipment of 10 units will be rejected. If a sample of three is selected , what is the probability that the shipment will be rejected?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
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A shipment of 10 items has two defective and eight non defective units.
In the inspection of the shipment, a sample of units will be selected and tested.
If a defective unit is found, the shipment of 10 units will be rejected.
If a sample of three is selected , what is the probability that the shipment will be rejected?
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The probability that the shipment will be rejected, is the ratio of two numbers.


The denominator is the number of all possible different triples of 10 items,

     =  = 120.



The numerator is the number of all triples of 10 item that contain one or two defective items.


The number of triples containing 1 defective item is   . =  = 8*7 = 56.

The number of triples containing 2 defective items is  . = 1*8 = 8.


Thus the numerator is  56 + 8 = 64.



Hence, the  ANSWER  to the problem's question is   = .

Solved.



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