SOLUTION: A submarine leaves the US base and travels 560 km due East at 54 kph and then 816 kmdue North At the same rate of speed, how long will it take it to get back to its base by t

Algebra.Com
Question 1188767: A submarine leaves the US base and travels 560 km due East
at 54 kph and then 816 kmdue North At the same rate of speed, how long will it
take it to get back to its base by the shortest route?

Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

Calculate the hypotenuse of the right angled triangle


    c =  = 989.67 kilometers


and then divide it by the rate of 54 km/h  to get the travel time


     = 18.33 hours   (rounded).    ANSWER

Solved.

---------------

In this solution, I neglect the fact that the Earth surface is spherical,
and consider it as flat.



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
There is no "rate of speed"
There's speed, and there's rate of movement.

RELATED QUESTIONS

``A submarine leaves the US base and travels 560 km due East at 54 kph and then 816... (answered by Alan3354,ikleyn)
Two buses leave the same station at 7:00PM. One bus travels north at the rate of 30 kph... (answered by mananth)
A train leaves Little Rock and travels north at 85 kph. Another train leaves at the same... (answered by Alan3354)
A ship leaves Sydney and travels due north for two hours at 24km/h, it then travels due... (answered by ankor@dixie-net.com)
A train leaves and travels north at 85 km per hour. Another train leaves at the same time (answered by Stitch,Alan3354)
two buses leave the same station at 7:00 pm. One bus travel north at the rate of kph and... (answered by rfer)
At the same starting point, Margeorie and Paula decided to run in opposite directions.... (answered by ikleyn)
A train travels due North for 450km at a rate of 65km/hr. It then turns sharply due East... (answered by addingup)
A freight train leaves a station and travels due east at a speed of 60 mph. One hour... (answered by Alan3354)