SOLUTION: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.

SOLUTION: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.

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Question 1188266: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Too many similar problems.
Make an effort.
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