SOLUTION: Put the equation
y=x2-8x+7 into the form y=(x-h)2+k
y=
Algebra.Com
Question 1188024: Put the equation
y=x2-8x+7 into the form y=(x-h)2+k
y=
Found 2 solutions by josgarithmetic, Solver92311:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
------------------------------------------
y=x^2-8x+7 into the form y=(x-h)^2+k
------------------------------------------
Complete-The-Square for the x.
Vertex would be (4,-9).
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Complete the square:
Divide the first-degree term by 2, square the result, and both add and subtract that value from the RHS. -8 divided by 2 is -4, -4 squared is 16, add and subtract 16 from the right-hand side:
Now the first three terms in the RHS are a perfect square, namely ^2)
, so:
^2\ -\ 9)
Check the answer:
The vertex of \ =\ ax^2\ +\ bx\ +\ c)
is the point \))
}{2(1)}\ =\ 4)
\ =\ 4^2\ -\ 8(4)\ +\ 7\ =\ -9\-)
John
My calculator said it, I believe it, that settles it
From
I > Ø
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