SOLUTION: Find the area bounded by the equation x/-5 + y/2=1on the first quadrant and the line x = 10.

Question 1186100: Find the area bounded by the equation x/-5 + y/2=1on the first quadrant and the line x = 10.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
given:

--------------------
....multiply by

intersection point is at(,)
find y

=> intersection point is at(,)

distance between (,) and (,) is units

the area bounded by the lines on the first quadrant is the area of a trapezoid which is equal to half the product of the height and the sum of the two bases

in your case, the sum of parallel sides is and perpendicular distance between the _parallel sides is
so, the area is

square units

RELATED QUESTIONS
Find the area bounded by the equation x/- 5 + y/2 = 1 on the first quadrant and the line... (answered by CPhill)

Find the area of the region in the first quadrant bounded by the line y=3x, the line x=5, (answered by MathLover1)

A right triangle in the first quadrant is bounded by lines y = 0, y = x, and y = -x+5.... (answered by Mathtut,gonzo)

I need help with this please: Find the area of the region in the first quadrant bounded... (answered by Boreal)

What is the area of the region bounded by the curves {{{ y = arcSin(x) + x - x^2 }}} and... (answered by robertb)

Find the area of the region bounded by the x and y axes and the line y= 2x... (answered by sachi)

find the area of the region bounded by two axes and the line... (answered by Fombitz)

find the area of the figure bounded by y = |x-3| -5 and the x-axis (answered by Fombitz)

The region bounded by curves y = x and y = x^2 in the first quadrant of the xy-plane is... (answered by ewatrrr)