SOLUTION: A long-jumper leaves the ground at an angle of 20º ablve the horizontal at a speed of 11m/s. (a) how far does he jump in the horizontal direction? (b) what is the maximum height r

Question 1181261: A long-jumper leaves the ground at an angle of 20º ablve the horizontal at a speed of 11m/s. (a) how far does he jump in the horizontal direction? (b) what is the maximum height reached?
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let v0= the initial speed = 11 m/s
Then the time to reach maximum height = t = v0sin(20)/g = 0.3835 s
The total flight time = t_tot = 2*0.3835 = 0.7670 s
The max. height h = (v0sin(20))^2/(2g) = 0.7214 m
The range in the horizontal direction = v0cos(20)*t_tot = 11*0.9397*0.767
= 7.928 m
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