SOLUTION: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?) options for first set of ?'s a. (7,2) b. (2,7) c. (-2,7) options for second set of

Algebra ->  Finance -> SOLUTION: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?) options for first set of ?'s a. (7,2) b. (2,7) c. (-2,7) options for second set of      Log On


   

Question 1180257: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?)
options for first set of ?'s
a. (7,2)
b. (2,7)
c. (-2,7)
options for second set of ?'s
a. (2,-3)
b. (-3,2)
c. (-2,-3)
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!

The equation %28y-2%29%5E2%2F3%5E2-%28x-2%29%5E2%2F4%5E2=1 represents a hyperbola whose
foci are (?,?) and (?,?)
%28y-2%29%5E2%2F3%5E2-%28x-2%29%5E2%2F4%5E2=1 =>Up-down hyperbola, h=2,k=2, a=3, b=4
foci: (?,?)
For an up-down facing hyperbola, the foci (focus points ) are defined as (h, k%2Bc ), (h, k-c+)
options for first set of ?'s
(h, k%2Bc )
we need to calculate c
c=sqrt%28a%5E2%2Bb%5E2%29
c=sqrt%283%5E2%2B4%5E2%29
c=sqrt%289%2B16%29
c=sqrt%2825%29
c=5
then foci is at (2, 2%2B5 )=> (2, 7 )
answer: b. (2,7)

options for second set of ?'s
(2, 2-5)=>(2, -3+)
answer: a. (2,-3)