SOLUTION: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?) options for first set of ?'s a. (7,2) b. (2,7) c. (-2,7) options for second set of

Question 1180257: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?)
options for first set of ?'s
a. (7,2)
b. (2,7)
c. (-2,7)
options for second set of ?'s
a. (2,-3)
b. (-3,2)
c. (-2,-3)
Answer by MathLover1(20855) (Show Source): You can put this solution on YOUR website!

The equation represents a hyperbola whose
foci are (?,?) and (?,?)
=>Up-down hyperbola, ,, ,
foci: (?,?)
For an up-down facing hyperbola, the foci (focus points ) are defined as (, ), (, )
options for first set of ?'s
(, )
we need to calculate

then foci is at (, )=> (, )
answer: b. (,)

options for second set of ?'s
(, )=>(, )
answer: a. (,)

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