SOLUTION: The hyperbolic cross-section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, an
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Question 1180218: The hyperbolic cross-section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.
The diameter at the center of the tower is ? meters
The center of the tower is ? meters above the ground.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
........complete squares
...........
...........both sides divide by
=> , , ,
center is at (,)
The diameter at the center of the tower is meters ( from each side of the center)
The center of the tower is meters above the ground. (y coordinates of the center)
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