SOLUTION: a train travels 30 miles in 5/6 the amount of time it takes a man to drive a car the same distance. if the rate of the train exceeds the rate of the car by 8 miles per hour, find t

Question 1177601: a train travels 30 miles in 5/6 the amount of time it takes a man to drive a car the same distance. if the rate of the train exceeds the rate of the car by 8 miles per hour, find the rate at which the car is traveling.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!

SPEEDS TIME DISTANCE TRAIN 5x/6 30 CAR x 30 DFFRNCE 8

You may see an equation you can form but the variable is the time, x, for the car.

RESULTS
Time for car, ;
Train speed, 48 mph;
Car speed, 40 mph
Answer by ikleyn(52884)   (Show Source): You can put this solution on YOUR website!
.

            Having the solution, as it is written and presented in the post by @josgarithmetic,
            I feel the need to REWRITE it from the scratch,

            since his presentation is below any acceptable level.

Let x be the car's rate, in miles per hour. Then the car's time traveled is = hours. According to the condition, then the train's time traveled is = = = hours. Thus the train's rate is = = . We are given that the difference of rates is 8 miles per hour. It means - x = 8. To solve this equation, multiply both sides by 5. You will get 6x - 5x = 40 x = 40. Thus the rate of the car is 40 miles per hour.

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Solved and presented in a way,   as it SHOULD be DONE.

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