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The average number of homes sold by the GBRAR is four (4) homes per day.
What is the probability that exactly six (6) homes will be sold tomorrow?
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The problem does not state that the only Poisson distribution can be used.
Therefore, totally different (but still reasonable approach) can be developed and applied.
Let's consider a random discrete variable X of the number of sold homes with integer values
from 0 to 8 inclusive, uniformly distributed.
Such random variable satisfies the given restriction, having 4 homes per day as the average.
Then we have the discretely distributed random variable having 9 possible values from 0 to 8 inclusive
with the probability for each discrete individual value.
Then P(X=6) = = 0.1111... ANSWER
Solved (differently).
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What is interesting, this answer of 0.1111 is not too far from the value of 0.1042,
obtained by @Boreal with the use of the Poisson distribution.