There are two commonly accepted ways to consider / solve the problems on depreciated values. One way is to consider a linear model with the slope coefficient m = -0.05. Another way is to consider exponential decrease of the depreciated value with the multiplication coefficient of (1- 0.05) = 0.95. In the first case, the depreciate value of the car after 12 years is V = 20700 - 0.05*20700*12 = 8,280 dollars. In the second case, the depreciate value after 12 years is V == 11,185 dollars.