SOLUTION: Find the minimum value of the quadratic y = 2x2 - 8x + 10 by completing the square.
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Question 1173689: Find the minimum value of the quadratic y = 2x2 - 8x + 10 by completing the square.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
y=2x^2-8x+10
=2(x^2-4x) + 10
the constant term is half the x term squared, or 4
=2(x^2-4x+4)+10-8, to keep the equation in balance
y=2(x-2)^2+2
the vertex is at (2, 2)
y=2 is the value
-
check
the vertex x value is at -b/2a=8/4=2
f(2)=8-16+10=2
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